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Q.

Two cars P and Q start from a point at the same time in a straight line and their positions are represented by xp(t) = at + bt2 and xq(t) = ft – t2. At what time do the cars have the same velocity?

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a

a+f2(b−1)

b

a+f2(1+b)

c

f−a2(1+b)

d

a−f1+b

answer is D.

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Detailed Solution

xp=at+bt2;xq=ft−t2dxpdt=a+2bt;dxqdt=f−2t

when, vp=vq

a+2bt=f−2t⇒t=f−a2(b+1)

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