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Two cars X and Y are approaching each other with velocities $36 k m p h$ and $72 kmph$ respectively. The frequency of a whistle sound as emitted by passenger in car X, heard by the passenger in car $Y$ is $1320 Hz$ . If the velocity of sound in air is $340 {ms}^{- 1}$ , the actual frequency of the whistle sound produced is

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1210 Hz

1230 Hz

1310Hz

1340 Hz

answer is A.

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Detailed Solution

$f = f_{0} {[\frac{v + v_{0}}{V - V_{s}}]}_{-}$

$320 = f_{0} [\frac{340 + 20}{340 - 10}] \to γ_{0} = 1210 Hz .$

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