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Two cells of emf 1V, 2V and each of internal resistance 1 $Ω$ are connected in parallel the effective voltage is

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1.5 V

2 V

0.5 V

1 V

answer is C.

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Detailed Solution

$E^{'} = \frac{E_{1} r_{2} + E_{2} r_{1}}{r_{1} + r_{2}}; E^{'} = \frac{1 \times 1 + 2 \times 1}{1 + 1} = 1 .5 V$

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