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Q.

Two charged particles are placed at a distance of 1.0 cm apart. What is the minimum possible magnitude of electrostatic force acting on each charge.

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a

25 x10-24N

b

2.3 x 10-24N

c

23 x10-24N

d

2.3 x10-24 dyne

answer is D.

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Detailed Solution

Fmin=14πε0e×er2=9×109×1.6×1019×1.6×10191×1022=2.3×1024N
(min. charge = one electron charge)

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