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Two charges 12µC and –6µC are separated by a distance of 20cm. The net electric potential is zero on the line joining them.

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at a distance of 0.2m from –6µc outside the charges

none of the above

both of the above

at a distance of 6.7cm from –6µ C in between the charges

answer is C.

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Detailed Solution

$\frac{12}{x} = \frac{6}{20 - x} \Rightarrow x = 13 .3 cm$
6.7 cm from 6µc between the charges
$\frac{6}{y} = \frac{12}{20 + y} \Rightarrow y = 20 cm$ from -6µc
outside the charges

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