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Q.

Two charges 14 μC and -4 μC are placed at (-12 cm, 0, 0) and (12 cm, 0, 0) in an external electric field E=Br2 where B=1.2×106N/cm2 are r is in metres. The electrostatic potential energy of the configuration is

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a

102.1 J

b

97.9 J

c

2.1 J

d

-97.9 J

answer is A.

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Detailed Solution

UE=kq1q2r
UE = electric potential energy
k =Coulomb constant
q1, q2 = charges
r = distance of separation
E=Br2
By substituting the given values, electrostatic potential energy of the configuration is 97.9J

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Two charges 14 μC and -4 μC are placed at (-12 cm, 0, 0) and (12 cm, 0, 0) in an external electric field E=Br2 where B=1.2×106N/cm2 are r is in metres. The electrostatic potential energy of the configuration is