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Two charges +2C and +6 C are repelling each other with a force of 12 N. If each charge is given -2 C of charge, then the value of the force will be

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zero

4 N (Attractive)

8 N (Repulsive)

4 N (Repulsive)

answer is D.

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Detailed Solution

Resultant charges after adding - 2 Care (-2 + 2) = 0

$and (- 2 + 6) = + 4 C \Rightarrow F = \frac{{kQ}_{1} Q_{2}}{r^{2}} = k \times \frac{0 \times 4}{r^{2}} = 0$

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