Q.

Two charges  3×108C and  2×108C  are separated by 15 cm in air. The distance of point where electric potential is zero is ( electric potential at infinity is zero)

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a

9 cm from positive charge in between the charges

b

9 cm from both the charges on perpendicular bisector of the line joining the in between the charges

c

30 cm from positive charge outside the charges

d

9 cm from negative charge in between the charges 

answer is B.

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Detailed Solution

3x=215x2x=453x

x=9cm from 3×108charge

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Two charges  3×10−8 C and  −2×10−8 C  are separated by 15 cm in air. The distance of point where electric potential is zero is ( electric potential at infinity is zero)