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Q.

Two charges 5 μC and 4  μC are separated by a distance 20 cm in air. Work to be done to decrease the distance to 10 cm is:

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a

2.7 J

b

0.45 J

c

1.8 J

d

0.9 J

answer is D.

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Detailed Solution

W=U2−U1⇒W=14π∈0q1q21r2−1r1 ⇒W=9×109×5×10-64×10-610.1−10.2=0.9J

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