Q.

Two charges each equal to ηqη1<3 are placed at the corners of an equilateral triangle of side a. The electric field at the third corner is E3

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a

E3=E0

b

E3>E0

c

E3<E0

d

E3<E0 where E0=q/4πε0a2

answer is C.

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Detailed Solution

E1=ηq4πε0a2,E2=ηq4πε0a2 Therefore E3=E1+E2 E3=E12+E22+2E1E2cos60=3ηq4πε0a2 Since η1<31<3η3η>1 3ηq4πε0a2>q4πε0a2E3>E0                here E0=q4πε0a2

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