Q.

Two charges of equal magnitude and at a distance ‘r’ exert a force F on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is

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a

F/8

b

F/16

c

F/4

d

4F

answer is D.

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Detailed Solution

Given data: a force F is applied between two charges of equal magnitude and separation r. Increasing the distance between them while halving the charges. 

Concept used: properties of electric charge

Detailed solution:

Force , F= kq22(2r)2=116F

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