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Two charges +q and –q are attached to the two ends of a light rod of length L, as shown in figure. The system is given a velocity v perpendicular to magnetic field B . The magnetic force on the system of charges and magnitude of force on one charge by the rod, are respectively.

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zero, zero

zero, qvB

2qvB, 0

2qvB, qvB

answer is B.

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Detailed Solution

F=qvB

On +q , force will be in upward direction while on -q force will be in downward direction.

hence, net force on the system will be zero.

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