Two charges Q1 = 18 μC and Q2 = -2 μC are separated by a distance R, and Q1 is on the left of Q2. The distance of the point where the net electric field is zero is

Neutral point is obtained at point P located at distance x on right of Q2∴kQ2x2=kQ1(x+R)2 put Q2=2μC and Q1=18μC ⇒x+Rx=3 ⇒ x=R2OR ⇒x=dq2q1-1=R182-1=R2

Two charges Q1 = 18 μC and Q2 = -2 μC are separated by a distance R, and Q1 is on the left of Q2. The distance of the point where the net electric field is zero is

Neutral point is obtained at point P located at distance x on right of Q2∴kQ2x2=kQ1(x+R)2 put Q2=2μC and Q1=18μC ⇒x+Rx=3 ⇒ x=R2OR ⇒x=dq2q1-1=R182-1=R2

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Two charges Q₁ = 18 $μ$ C and Q₂= -2 $μ$ C are separated by a distance R, and Q₁ is on the left of Q₂. The distance of the point where the net electric field is zero is

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left of Q₁ at R/2

right of Q₂ at R

right of Q₂ at R/2

between Q₁ and Q₂

answer is D.

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Detailed Solution

Neutral point is obtained at point P located at distance x on right of Q₂

$∴ \frac{k |Q_{2}|}{x^{2}} = \frac{k |Q_{1}|}{(x + R)^{2}} p u t |Q_{2}| = 2 μ C a n d |Q_{1}| = 18 μ C \Rightarrow \frac{x + R}{x} = 3 \Rightarrow x = \frac{R}{2}$