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Two charges $Q_{1} = 18 μ C$ and $Q_{2} = - 2 μ C$ are separated by a distance R, and $Q_{1}$ is on the left of $Q_{2}$ . The distance of the point where the net electric field is zero is

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between $Q_{1}$ and $Q_{2}$

left of $Q_{1}$ at $R / 2$

right of $Q_{2}$ at R

right of $Q_{2}$ at $R / 2$

answer is D.

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Detailed Solution

$\frac{k Q_{2}}{x^{2}} = \frac{k Q_{1}}{{(x + R)}^{2}}$ or $x = \frac{R}{2}$ Question Image

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