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Two charges $Q_{1} and Q_{2}$ are placed at the points A and B having separation. r, one charge lying inside and the other charge lying outside an uncharged conducting shell. The force on $Q_{1}$ is F and that on $Q_{2}$ is f. Then

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$F = 0$

$f = \frac{1}{4 π \in_{0}} \frac{Q_{1} Q_{2}}{r^{2}}$

$F = \frac{1}{8 π \in_{0}} \frac{Q_{1} Q_{2}}{r^{3}}$

$F = \frac{1}{8 π \in_{0}} \frac{Q_{1} Q_{2}}{r^{2}}$

answer is A, C.

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Detailed Solution

Net electric field inside a hollow charged conductor, due to charges on its surface and due to charges outside it, is zero.

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