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Two charges $2 nC$ and $- 6 nC$ are separated by 16 cm in air. The resultant electric intensity at the zero potential point which lies in between them and on the line joining them is

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7500 NC^-1

15000 NC^-1

450 NC^-1

1.5 NC^-1

answer is A.

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Detailed Solution

Let the point is P.

$V_{P} = 0 (Given)$

$\Rightarrow V_{1} + V_{2} = 0$

$\Rightarrow \frac{1}{4 π \in_{0}} \frac{2 \times 10^{- 9}}{x} = \frac{1}{4 {πϵ}_{0}} \frac{6 \times 10^{- 9}}{16 - x}$

$\Rightarrow x = 4 c m$

$At P, E = 9 \times 10^{9} \frac{2 \times 10^{- 9}}{x^{2}} + 9 \times 10^{9} \frac{6 \times 10^{- 9}}{(16 - x)^{2}}$

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