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Two chords AB and CD of a circle intersect each other at point E on side of the circle. If $A B = 11 cm$ , $B E = 3$ cm , $D E = 3.5$ cm, then $C D =$

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10.5 cm

9.5 cm

8.5 cm

7.5 cm

answer is C.

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Detailed Solution

E A \times E B = E C \times E D

$(3 + 11) \times 3 = (3.5 + x) \times 3.5$

$3.5 + x = 12$

$x = 12 - 3.5 = 8.5 c m$

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