Q.

Two circles  C1  and  C2  of radii 8 each are placed inside a semicircle C of radius 25. The 
two circles C1  and  C2  are each tangent to the diameter of semicircle C and also tangent  to the semicircle C. The length of direct common tangent of  C1  and  C2 is  a, The length  of transverse common tangent of C1  and  C2 is b and The inradius of triangle formed by  joining centers of circles C,C1,C2  is c. Then the value of  a+b2+c  is ___

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answer is 677.75.

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Detailed Solution

Distance between centre = 30
Question Image 
 L.D.C=30 L.T.C=(30)2(8+8)2 =302162=46×14 =2161
Also  =12×30×8=120
 r=ΔΔ=12017+17+302=120×264=24064=308=154

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