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Q.

Two circles touch externally. The sum of their areas is 130π sq.cm. and the distance between their centre is 14cm. Find the radii of the circles ____.


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Detailed Solution

Let us consider two circles with r1 and r2 as their radii and the larger be having the radii as r1
   Question ImageNow we are given that the distance between the centres of the circles is 14cm that is-  r1+r2=14cm

So we get the needed relation between the r1 and r2

Now also the sum of the areas of the two circles is 130πsq.cm. let us suppose the areas of the two circles be A1 and A2  so the another relation that is between the areas of the two circles is as- A1+A2=130.π.sq.cm
Now the area of any circle with radius r is as- πr2
Now the relation of the areas become πr12+πr22=130πsq.cm
Now taking like terms common and simplifying the terms we get –
π(r12+r22)=130πsq.cm----------------1
Now using the relation between the r1and r2 we will find the value of r2
in the form of the r1 that is -
Now putting the value of the r2from the above equation in the equation 1
that is
πr12+14-r122=130πsq.cm
Now removing π from both sides the above equation becomes –
r12+196+r12-28r1=130 ⇒2r1228r1+66=0
r12-14r1+33=0
r12-11r1-3r1+33=0
⇒(r1−11)( r1−3)=0
Now from the above equation we get the (r1−11) = 0 also (r1−3) = 0
Now  r1=11,3 now putting r1 in the equation r1+r2=14 cm we get r2=11,3
As depicted in the figure r1 and assumed earlier being the larger of the two r1=11cm and r2 =3 cm so from the above given options the option which matches the resultant is the option 1 that is 1) 11 cm and 3 cm. So the correct option is 1
 
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