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Q.

Two circular rings made of same wire having radii R and nR. Their moment of inertial about central axis is 1 : 8, the value of ‘n’ is

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a

2

b

8

c

1

d

4

answer is A.

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Detailed Solution

I = $M R^{2}$

I = (Vd) $R^{2}$

I = $(2 π R \times a) d . R^{2}$

$I \propto R^{3}$

$\frac{I_{1}}{I_{2}} = {(\frac{R}{n R})}^{3} = \frac{1}{8}$

n = 2

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