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Q.

Two circular rings of equal mass ‘m’ and radius ‘r’ are placed touching each other. The moment of inertia of the system about tangential axis in the plane of system passing through point of contact of rings is

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a

3 mr²

b

$\frac{3}{2} {mr}^{2}$

c

6 mr²

d

$\frac{5}{2} {mr}^{2}$

answer is A.

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Detailed Solution

MOI of ring about diameter= $\frac{M R^{2}}{2}$

MOI about tangent= $\frac{3 M R^{2}}{2}$

Hence MOI of system= $3 M R^{2}$

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Two circular rings of equal mass ‘m’ and radius ‘r’ are placed touching each other. The moment of inertia of the system about tangential axis in the plane of system passing through point of contact of rings is