Two circular wire of the same radius is pasted over each other. Coil 1 has current $I_{1}$ in a clockwise direction and coil 2 has a current $I_{2}$ in an anti-clockwise direction, what will be the direction of a magnetic field at the center if $(I_{1} > I_{2})$ .

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Out of the plane

Left

Right

Into the plane

answer is D.

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Detailed Solution

Two circular wire of the same radius is pasted over each other. Coil 1 has a current $I_{1}$ in a clockwise direction and coil 2 has a current $I_{2}$ in the anti-clockwise direction, what will be the direction of a magnetic field at the center if $(I_{1} > I_{2})$ is into the plane

By the Right-hand thumb Rule, the direction of the magnetic field at the center of the loop due to coil 1 will be into the plane and due to coil 2 will be out of the plane.

Since $I_{1} > I_{2}$

So $B_{1} > B_{2}$

So the direction of a magnetic field will be into the plane.

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