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Two cities are 150 km apart. Electric power is sent from one city to another city through copper wires. The fall of potential per km is 8 volt and the average resistance per km is 0.5 $Ω$ . The power loss in the wire is

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a

12.2 kW

b

19.2 J

c

19.2 W

d

19.2 kW

answer is A.

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Detailed Solution

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Fall of potential per km is 8V
∴ For 150km, fall in potential V = 8 x 150
average resistance per km is 0.5Ω
∴Resistance for 150km is R =150 × 0.5
∴ power loss, $P = \frac{V^{2}}{R}$
$= \frac{(8 \times 150)^{2}}{150 \times 0 .5} = \frac{8 \times 8 \times 150}{0 .5} = 19200 W = 19 .2 k W$

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