Two cities are 150 km apart. Electric power is sent from one city to another city through copper wires. The fall of potential per km is 8 volt and the average resistance per km is 0.5 $Ω$ . The power loss in the wire is

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19.2 kW

19.2 J

12.2 kW

19.2 W

answer is A.

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Detailed Solution

Here,

Distance between two cities = 150 km

Resistance of the wire, R = (0.5 $Ω$ $k m^{- 1}$ ) (150 km) = 75 $Ω$

Voltage drop across the wire

V = (8 V $k m^{- 1}$ ) (150 km) = 1200 V

Power loss in the wire is

$P = \frac{V^{2}}{R} = \frac{(1200 V)^{2}}{75 Ω} = 19200 W = 19.2 kW$

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