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Two cities X and Y are 70 km a part. Two cyclists start at the same time, one from X to Y and the other from Y to X. The first travelling at 20 kmph and the second at 15 kmph. A bird starts with the cyclist at X and flies to the other cyclist and returns. It keeps on flying from cyclist to cyclist till they meet each other. The bird travels at 25 kmph. What is distance travelled by the bird?

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45 km

70 km

35 km

50 km

answer is C.

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Detailed Solution

The time taken by cyclists to meet

$\frac{D i s \tan c e b e t w e e n t w o c i t i e s}{Re l a t i v e s p e e d}$

$\frac{70}{20 + 15} = \frac{70}{35} = 2 h o u r s$

The distance travelled by the bird.

$25 \times 2 = 50 k m s$

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