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Two cliff of heights 120m and 100.4m are separated by a horizontal distance of 16m. If a car has to reach from the first cliff to the second, the horizontal velocity of the car should be

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16 ms^-1

2 ms^-1

4 ms^-1

8 ms^-1

answer is D.

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Detailed Solution

h = 19.6m ; R = 16m
$\begin{array}{l} R = u \sqrt{\frac{2 h}{g}} \Rightarrow 16 = u \sqrt{\frac{2 \times 19.6}{9.8}} \\ u = \frac{16}{2} = 8 {ms}^{- 1} \end{array}$

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