Q.

Two coaxial circular loops of radii 0.5m and 5×102m are separated by a distance 0.5m and carry currents 2A and 1A respectively. What is the force between the loops?

Two coaxial circular loops of raadii `r_(1)` and `r_(2)` are separated by a  distance `x` and carry currents `i_(1)` and `i_(2)` respectively. Calculat  - Sarthaks eConnect | Largest Online Education Community

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a

-2.09×10-7N

b

-2.09×10-4N

c

-2.09×10-8N

d

None of these

answer is A.

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Detailed Solution

The potential energy of a coil in a magnetic field is 

where M2 is magnetic moment of coil 2 and B1 magnetic field on it. 

The force between the loops

F=-dUdx and U = - M2.B1

   =ddx[I2πR22]μ0I1R122(R12+x2)3/2=-3μ0I1I2R12R22x2(R12+x2)5/2

    =3×(10-7×4π)2×1×(0.5)2×(0.05)2×(0.5)2[(0.5)2+(0.5)2]5/2

F=-2.09×10-8N Ans.

The minus sign shows that the force is attractive.

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