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Two coherent light sources S₁and S₂ ( $λ$ = 6000 Å) are 1mm apart from each other. The screen is placed at a distance of 25 cm from the sources. The width of the fringes on the screen should be

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0.010 cm

0.015 cm

0.025 cm

0.030 cm

answer is A.

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Detailed Solution

$β = \frac{6000 \times 10^{- 10} \times 25 \times 10^{- 2}}{10^{- 3}} = 150000 \times 10^{- 9} = 0 .15 \times 10^{- 3} m = 0 .015 cm .$

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