Two coherent monochromatic light beams of intensities I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam are

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9I & 3I

9I & I

4I & I

5I & 3I

answer is C.

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Detailed Solution

$\begin{array}{l} I_{max} = {(\sqrt{I_{1}} + \sqrt{I_{2}})}^{2} = (\sqrt{I} + \sqrt{4 I})^{2} = 9 I \\ I_{min} = {(\sqrt{I_{1}} - \sqrt{I_{2}})}^{2} = (\sqrt{I} - \sqrt{4 I})^{2} = I \end{array}$

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