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Q.

Two coherent monochromatic light sources are located at two vertices of an equilateral triangle. If the intensity due to each of the source independently is 1 Wm-2 at the third vertex. The resultant intensity due to both the source at that point (i.e. at the third vertex) is (in Wm-2)

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a

Zero

b

\sqrt 2 \

c

2

d

4

answer is D.

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Detailed Solution

As the third vertex is at the same distance from the remaining two vertices then the path difference is zero. Hence the resultant intensity is

Imax=I1+I22

{I_{\max }} = {(1 + 1)^2} = 4\
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