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Two coherent monochromatic light sources are located at two vertices of an equilateral triangle. If the intensity due to each of the source independently is 1 Wm^-2 at the third vertex. The resultant intensity due to both the source at that point (i.e. at the third vertex) is (in Wm^-2)

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Zero

$\sqrt{2}$

answer is D.

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Detailed Solution

As the third vertex is at the same distance from the remaining two vertices then the path difference is zero. Hence the resultant intensity is 2 I_max = (1+ 1)² = 4

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