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Two coils have a mutual inductance 0.005 H. The current changes in first coil according to equation $I = I_{0}$ sin wt where I₀ = 2 A and $ω = 100 π$ rad/sec. The maximum value of emf in second coil is :

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4 $π$

3 $π$

2 $π$

$π$

answer is D.

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Detailed Solution

$e = M \frac{dI}{dt} = (0.005) x \frac{d}{dt} (I_{0} sinωt) = (0.005) (I_{0} ω cosωt) \Rightarrow e_{\max} = 0.005 x 2 x 100 π = π$

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