Two coils have mutual inductance 0.005 H. The current changes in the first coil according to equation $I = I_{0} \sin ωt, where I_{0} = 10 A and ω = 100 π {rads}^{- 1} .$ The maximum value of emf in the second coil is

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5 $π$

0.5 $π$

$π$

answer is B.

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Detailed Solution

Given data:

Mutual inductance M=0.005H, $I_{0} = 10 A$ , $ω = 100 π \frac{rad}{\sec}$ , $I = I_{0} sinωt$

Concept used: Induced EMF

Detailed solution:

$ε = M \frac{dI}{dt}$

$= M \frac{d}{dt} (I_{0} sinωt)$

$= 0.005 \times I_{0} \cos ω t \times ω$

$\Rightarrow ε_{\max} = 0.005 \times I_{0} \times ω = 5 π$

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