Two coils have self inductance L₁ = 4mH and L₂ = 1 mH. The currents in the coils are increased at the same rate. At a certain instant of time both coils are given the same power. If I₁ and I₂ are the currents in the two coils at that instant of time respectively then the value of (I₁/I₂) is

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answer is B.

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Detailed Solution

$\begin{array}{l} p = Ei; p = - L \frac{di}{dt} i; p = const, \frac{di}{dt} = Const \\ L \propto \frac{1}{i} \Rightarrow \frac{i_{1}}{i_{2}} = \frac{L_{2}}{L_{1}} = \frac{1}{4} \end{array}$

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