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Q.

Two coils have self inductance L1 = 4mH and L2 = 1 mH. The currents in the coils are increased at the same rate. At a certain instant of time both coils are given the same power. If I1 and I2 are the currents in the two coils at that instant of time respectively then the value of (I1/I2) is

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a

1/4

b

1

c

1/8

d

1/2

answer is B.

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Detailed Solution

p=Ei;p=Ldidti;p= constdidt= Const L1ii1i2=L2L1=14

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