Two coils of self inductance $L_{1}$ and $L_{2}$ are connected in series combination having mutual inductance of the coils as M. the equivalent self inductance of the combination will be :

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$L_{1} + L_{2} - 2 M$

$\frac{1}{L_{1}} + \frac{1}{L_{2}} + \frac{1}{M}$

$L_{1} + L_{2} + M$

$L_{1} + L_{2} + 2 M$

answer is D.

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Detailed Solution

If current in both inductor is in same direction then $L_{e q} = L_{1} + L_{2} + 2 M$ and, if current in both inductor is in opposite direction, then $L_{e q} = L_{1} + L_{2} - 2 M$

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