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Q.

Two coils of self-inductance L₁ and L₂ are connected in series, combination having mutual inductance of the coils as M. The equivalent self-inductance of the combination will be.

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a

$\frac{1}{L_{1}} + \frac{1}{L_{2}} + \frac{1}{M}$

b

$L_{1} + L_{2} + M$

c

$L_{1} + L_{2} + 2 M$

d

$L_{1} + L_{2} - 2 M$

answer is D.

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Detailed Solution

$L_{{e q}_{}} = L_{1} + L_{2} - 2 M$

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Two coils of self-inductance L1 and L2 are connected in series, combination having mutual inductance of the coils as M. The equivalent self-inductance of the combination will be.