Two coins are tossed simultaneously 500 times, and we get one tail 250 times. Find the probability of occurrence of one tail:

Given,

the total number of trials = 500

the number of trials in which the event of the occurrence of one tail = 250

Probability of an event happening P(E) = $\frac{\mathrm{Number} \mathrm{of} \mathrm{trials} \mathrm{in} \mathrm{which} \mathrm{the} \mathrm{event} \mathrm{happened}}{\mathrm{The} \mathrm{total} \mathrm{number} \mathrm{of} \mathrm{trials}}$

Therefore, the probability of occurrence of one tail P(E) =$\frac{250}{500}=\frac{1}{2}$