Two coins are tossed simultaneously. The probability of getting at most one head is:

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13

24

34

14

answer is C.

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Detailed Solution

Given that, 2 coins are tossed.
We have to find the probability of getting at most one head.
The probability of an event A is given by,

P (A) = Number of favourable outcomes T o t a l number of outcomes

The possible outcomes are {HH, HT, TH, TT}.
So, n(S) = 4.
So, the event of getting at most one head (A) is {HT, TH, TT}.
The frequency of getting heads one time and less or, number of times heads appears in 1 coin and no heads appear in any coin

⇒ n (A) = 2 + 1 ⇒ n (A) = 3

So, as per the formula, probability of getting almost one head is given by,

= N u m b e r of times heads appears in 1 coin a n d no head appeared i n any coin t o t a l number of possible events ⇒ P (A) = n (A) n (S) ⇒ P (A) = 34

Therefore, the probability of getting at most one head is

34

.
Hence, option 3 is the correct option.

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