Two communicating vessels contain mercury. The diameter of one vessel is four times larger than the diameter of the other. A column of water of height h0 = 70 cm is poured into the left hand vessel (the narrower one). How much will be mercury level rise in the right hand vessel? (Specific density of mercury= 13.6)

Due to water, equal volume of mercury displaced.70 cm ×ρwg=(16x+x)ρHg g ⇒ x=0.3 cm

Two communicating vessels contain mercury. The diameter of one vessel is four times larger than the diameter of the other. A column of water of height h0 = 70 cm is poured into the left hand vessel (the narrower one). How much will be mercury level rise in the right hand vessel? (Specific density of mercury= 13.6)

Due to water, equal volume of mercury displaced.70 cm ×ρwg=(16x+x)ρHg g ⇒ x=0.3 cm

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Two communicating vessels contain mercury. The diameter of one vessel is four times larger than the diameter of the other. A column of water of height h₀ = 70 cm is poured into the left hand vessel (the narrower one). How much will be mercury level rise in the right hand vessel? (Specific density of mercury= 13.6)

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Detailed Solution

Due to water, equal volume of mercury displaced.
$70 cm \times ρ_{w} g = (16 x + x) ρ_{Hg} g \Rightarrow x = 0.3 cm$

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