Two concentric coils X and Y of radii 16cm and 10cm respectively lie in the same vertical plane containing the north to south direction. Coil X has 20 turns and carries a current of 16 A, Coil Y has 25 turns and carries a current of18A.The sense of the current is anti clockwise in X and clockwise in Y, for an observer facing west. The net magnetic field due to the cash at their common. Center is

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$1.6 \times 10^{- 3} T, west$

$1.6 \times 10^{- 3} T, East$

$3.2 \times 10^{- 6} T, East$

$3.2 \times 10^{- 6} T, west$

answer is A.

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Detailed Solution

$B = \frac{μ_{o} iN}{2 r} ∴ B_{net} = B_{Y} - B_{X} = \frac{4 π \times 10^{- 7}}{2} [\frac{25 \times 18}{0.1} - \frac{20 \times 16}{0.16}] T = 1.6 \times 10^{- 3} T, West$

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