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Two concentric metallic shells are of radii $r_{1}$ and $r_{2} (r_{2} > r_{1})$ . If charge given to the outer sphere is q, and the inner sphere is ground. Then the charge on the inner sphere q1 is

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Zero

$- q$

$- \frac{r_{1}}{r_{2}} q$

$\frac{r_{1}}{r_{2}} q$

answer is C.

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Detailed Solution

$\frac{1}{4 π \in_{0}} [\frac{q}{r_{2}} + \frac{q^{1}}{r_{1}}] = 0$ Potential of inner sphere is zero.

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