Two concentric, thin, metallic spheres of radii R1, and R2 (R1 > R2 ) bear charges Q1 and Q2 respectively as shown in fig. Then the potential at radius r between .R1 and R2, will be 1/4πε0times

Vr = potential at P due to Q1 + potential at P due to Q2V1=14πε0×Q1R1 and V2=14πε0×Q2r∴ VI=V1+V2=14πε0Q1R1+Q2r

Two concentric, thin, metallic spheres of radii R1, and R2 (R1 > R2 ) bear charges Q1 and Q2 respectively as shown in fig. Then the potential at radius r between .R1 and R2, will be 1/4πε0times

Vr = potential at P due to Q1 + potential at P due to Q2V1=14πε0×Q1R1 and V2=14πε0×Q2r∴ VI=V1+V2=14πε0Q1R1+Q2r

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Two concentric, thin, metallic spheres of radii R₁, and R₂ (R₁ > R₂ ) bear charges Q_{1 and} Q₂ respectively as shown in fig. Then the potential at radius r between .R₁ and R₂, will be $1 / 4 {πε}_{0}$ times

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

$\frac{Q_{1} + Q_{2}}{r}$

$\frac{Q_{1}}{R_{2}} + \frac{Q_{2}}{R_{1}}$

$\frac{Q_{1}}{R_{1}} + \frac{Q_{2}}{r}$

$\frac{Q_{1}}{R_{1}} + \frac{Q_{2}}{R_{2}}$

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

V_r = potential at P due to Q₁ + potential at P due to Q₂
$V_{1} = \frac{1}{4 {πε}_{0}} \times \frac{Q_{1}}{R_{1}} and V_{2} = \frac{1}{4 {πε}_{0}} \times \frac{Q_{2}}{r}$
$∴ V_{I} = V_{1} + V_{2} = \frac{1}{4 {πε}_{0}} [\frac{Q_{1}}{R_{1}} + \frac{Q_{2}}{r}]$