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Q.

Two concentric, thin, metallic spheres of radii R1, and R2 (R1 > R2 ) bear charges Q1 and Q2 respectively as shown in fig. Then the potential at radius r between .R1 and R2, will be 1/4πε0times

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a

Q1+Q2r

b

Q1R2+Q2R1

c

Q1R1+Q2r

d

Q1R1+Q2R2

answer is B.

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Detailed Solution

Vr = potential at P due to Q1 + potential at P due to Q2
V1=14πε0×Q1R1 and V2=14πε0×Q2r
 VI=V1+V2=14πε0Q1R1+Q2r

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