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Two condensers of capacities $2 μF$ and $3 μ F$ are connected in parallel with a battery. If the energy stored in $2 μF$ is E. Then the energy stored in condenser of capacity $3 μ F$ are

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$\frac{3}{2} E$

$\frac{2}{5} E$

$\frac{2}{3} E$

answer is B.

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Detailed Solution

$V = \frac{q_{1}}{C_{1}} = \frac{q_{2}}{C_{2}} \Rightarrow q_{2} = \frac{3 Q}{2}$

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