Two conductors are made of the same material and have the same length. Conductor A is a solid wire of diameter 1.0 mm. Conductor B is a hollow tube of outside diameter 2.0 mm and inside diameter 1.0 mm. The resistance ratio R_A/R_B will be

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answer is C.

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Detailed Solution

$R e s i s \tan c e o f t h e f i r s t w i r e R_{1} = \frac{ρ l}{π {(0.5)}^{2}} = \frac{4 ρ l}{π}$

$R e s i s \tan c e o f t h e t u b e R_{2} = \frac{ρ l}{π (1^{2} - 0 . 5^{2})} = \frac{4 ρ l}{π 3}$

$ratio = \frac{3}{1}$

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