Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Two constant forces F1 and F2 act on a body of mass 8 kg. These forces displace the body from point P (1, -2, 3) to Q (2, 3, 7) in 2s starting from rest. Force F1 is of magnitude 9 N and is acting along vector (2i^2j^+k^). Work done by the force F2 is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

180 J

b

80 J

c

-180 J

d

-80 J

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

s=i^+5j^+4k^=12F1+F2m(2)2   ...........(i)F1=9(2i^2j^+k^)22+22+1=6i^6j^+3k^    ...........(ii)
From Eqs.(i) and (ii), F2=-2i^+26j^+13k^)
Work done by F2:W=F2s=180J

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring