Two convex lenses of powers 4D and 6D are separated by a distance of 16m . The power of the optical system so formed is

P=P1+P2-dP1P2 P=6+4-16×6×4=6D

Two convex lenses of powers 4D and 6D are separated by a distance of 16m . The power of the optical system so formed is

P=P1+P2-dP1P2 P=6+4-16×6×4=6D

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Two convex lenses of powers 4D and 6D are separated by a distance of $\frac{1}{6} m$ . The power of the optical system so formed is

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$- 6 D$

$+ 6 D$

$10 D$

$2 D$

answer is B.

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Detailed Solution

$P = P_{1} + P_{2} - d P_{1} P_{2} P = 6 + 4 - \frac{1}{6} \times 6 \times 4 = 6 D$

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Two convex lenses of powers 4D and 6D are separated by a distance of 16m . The power of the optical system so formed is

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Two convex lenses of powers 4D and 6D are separated by a distance of $\frac{1}{6} m$ . The power of the optical system so formed is