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Two dice are rolled simultaneously. The probability of getting an even number and an odd number is

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$\frac{5}{6}$

$\frac{9}{13}$

$\frac{1}{2}$

$\frac{1}{4}$

answer is C.

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Detailed Solution

$n (S) = 6^{2} = 36$

$E =$ getting even no on one dice and odd no. on another dice

$n (E) = 3 \times 3 \times 2 = 18, P (E) = \frac{18}{36} = \frac{1}{2}$

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