Two dice are rolled. What is the probability that none of the dice shows the number 2 ?

Two dies are rolled then $n\left(S\right)=6^2=3^6$
$E$ be the event of none of the die shows ‘2’

$n\left(E\right){=}^5{C}_1{\cdot }^5{C}_1=25$ 

  $P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{25}{36}$