Two dice are thrown, then what is the probability of getting the sum of two results as perfect squares if it is known that number 3 will always come on the 1st die?

Here Sample Space S = {(3, 1), (3, 2), (3, 3), (3, 4), (3,5) and (3, 6)}.

 So number of elements is 6. And the favorable case is {(3, 1) 

and (3, 6)} So required probability is 2/6 = 1/3