Two dices are rolled. If both dices have six faces numbered 1, 2, 3, 5, 7 and 11, then the probability that the sum of the numbers on the top faces is less than or equal to 8 is $λ$ then $\frac{72 λ}{17} =$

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Detailed Solution

Favorable ordered pairs for the event E

${\begin{cases} (1, 1), (1, 2) (1, 3) (1, 5), (1, 7), (2, 1), (2, 2), (2, 3), (2, 5),, \\ (3, 1), (3, 2), (3, 3), (3, 5), (5, 1), (5, 2), (5, 3), (7, 1) \end{cases}}$

$\begin{array}{l} n (E) = 17, n (S) = 36 \\ P (E) = \frac{17}{36} \end{array}$

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